First input argument must be a function handle.
1 view (last 30 days)
Show older comments
Hi, I am trying to integrate using the following function:
if true
syms h g x pi
h = 2.0545
g = 5.3442
C = 1
y = C - (exp(-2.*g.*i.*x./h)).*(C - cos(x).*((h.^2)./2) + (g.*x)/2.*h.*i)
yx = integral(y,-pi,pi)
end
however, I get the error "First input argument must be a function handle. "
Can anyone suggest a solution?
Thanks!
0 Comments
Accepted Answer
KSSV
on 10 Aug 2017
h = 2.0545 ;
g = 5.3442 ;
C = 1 ;
y = @(x) C - (exp(-2.*g.*1i.*x./h)).*(C - cos(x).*((h.^2)./2) + (g.*x)/2.*h.*1i) ;
yx = integral(y,-pi,pi)
3 Comments
José-Luis
on 10 Aug 2017
y = @(x) ((C - (exp(-2.*g.*i.*x./h)).*C) * ((C - (exp(-2.*g.*-i.*x./h)).*C);
In your anonymous function the @(x) is not the symbolic variable x.
More Answers (0)
See Also
Categories
Find more on Assumptions in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!