anonymous function issue

Hi guys I need help with this issue

I am using this calculated formula

(((h(n)/3)*(f(c)+Ie+Io+f(d))))

which equals to

(x*exp(1/2 - x))/24 + (x*exp(1/4 - x))/12
where, f=@(y) (x*y*exp(y-x)),

then i wrote it as

g =  @(x)(((h(n)/3)*(f(c)+Ie+Io+f(d))))

then i tried which is in my code

>> g(2)

ans =

(x*exp(1/2 - x))/24 + (x*exp(1/4 - x))/12

I am wondering why it gives me the same formula without substituting x as 2

Answer 1

[Walter Roberson]

You use x as the dummy parameter for g, but you do not use x within the formula.

In order for your code not to crash you would have to have defined x as symbolic or given x a value before you defined f, and it would be that symbol or that value that would be "captured" in the definition of f.

For example,

x = 5;
f = @(y) 3 + x + y;
x = 19;
f(7)

then the value "x = 5" gets "captured" when f is defined so even though you changed x after you define f, the value 5 will be used not the current x.

[Abdulaziz]

thanks your notes drives me to my mistake