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distance between array entries

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amateurintraining
amateurintraining on 29 Nov 2017
Commented: Andrei Bobrov on 29 Nov 2017
How do you write code to get which of the entries stored in an array it is closest to for each data point?
For example:
array: [4 9 7 3 10 19 2 11]
and you want to find which entry each entry is closest to. So, in the above array, the answer would be:
[4 5 2 1 2 8 4 5]
(the number 4 is closest in value to the 4th entry in the array...the number 9 is closest in value to the 5th entry in the array...etc.)
  1 Comment
Jos (10584)
Jos (10584) on 29 Nov 2017
You should define " closest" more accurately! Why is 9 closer to 10 rather than 11? And I would argue that any number is closest to itself, so 1:8 would be my answer ;)

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Answers (3)

KSSV
KSSV on 29 Nov 2017
Edited: KSSV on 29 Nov 2017
Read about knnsearch.
A = [4 9 7 3 10 19 2 11] ;
B = [4 5 2 1 2 8 4 5] ;
idx = knnsearch(A',A','k',2) ;
iwant = idx(:,2)

Andrei Bobrov
Andrei Bobrov on 29 Nov 2017
a = [4 9 7 3 10 19 2 11];
[~,iout] = min(abs(a(:)-a(:)')+diag(nan(numel(a),1)),[],2);

Roger Stafford
Roger Stafford on 29 Nov 2017
Let 'a' be your array (row vector.)
n = size(a,2);
[t,p] = sort(a);
q = 1:n; q(p) = q;
t = diff(t);
t = [inf,t;t,inf];
[~,r] = min(t);
r = (1:n)+2*r-3;
p = p(r(q)); % p is the desired result

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