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Allocating values in 1d matrix

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Da'Moon on 6 Dec 2017
Edited: Da'Moon on 6 Dec 2017
B = p * ones(327,245,2, uint8); can i do it with a loop?

Accepted Answer

Image Analyst
Image Analyst on 6 Dec 2017
No need for for loops, especially ones that don't work. Simply use ones:
B = p * ones(327,245,2, 'uint8');
  1 Comment
Image Analyst
Image Analyst on 6 Dec 2017
Try this:
for L = 3 : -1 : 1
for row = 327 : -1 : 1
for col = 245 : -1 : 1
B(row, col, L)=p;
It's a very inefficient way of doing it. I reverse the indexes to try to make it more efficient though. You should NOT want to do it this way.

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