# How to flip values greater than zero in a row

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Tanmoyee Bhattacharya on 16 Apr 2018
Edited: Stephen23 on 16 Apr 2018
If I have a row in matrix like that
0 0 0 0 1 2 3 0 0 0
I want to make it like that
0 0 0 0 0 0 3 2 1 0
If it is possible to do?
Stephen23 on 16 Apr 2018
@Tanmoyee Bhattacharya: the numbers a not only flipped L-R, but have been translated too. How is the new position determined?

Birdman on 16 Apr 2018

Try this:

```A=[0 0 0 0 1 2 3 0 0 0]
idx=find(A~=0);
A(idx+nnz(A)-1)=fliplr(A(idx));
A(idx(1:end-1))=0
```
Tanmoyee Bhattacharya on 16 Apr 2018
Edited: Stephen23 on 16 Apr 2018
Thank you so much sir.It is very much useful. It is working for one row perfectly.I have multiple rows Two are
A=[0 0 0 0 0 0.105037027 0.894962973 0 0 0
;0 0 0 0 0 0 0.990679262 0.009320738 0 0
];
It should be like
0
0 0 0 0 0 0.894962973 0.105037027 0 0
0 0 0 0 0 0 0 0.009320738 0.990679262 0
But the result is coming
0 0 0 0 0 0 0 0 0.990679262000000 0.00932073800000000
0 0 0 0 0 0 0 0.894962973000000 0 0
For many rows how to change the code?