Generation of a column with constants values that increases for different RANGE of row

I'm trying to generate ONE column of numbers in Matlab as follows:

1) let the value be equal 10 for row 1 to 30,

2) let the value be equal 10 + increment (for example increment=8) for row 31 to 60,

3) let the value increase in increments of 8 for each new sequence of row 1 to 30

until final constant value equals a number, (for example, 82)

I tried a loop like this:

for f =1:30

for g=(10:8:82);

    h(f,1) = g;
end;end;
but did not work.
My result is only a column with the constant 82
from row 1 until 30.

I wonder if someone could help me.

Thanks

Emerson

Answer 1

[Oleg Komarov]

1) A( 1:30,1) = 10;
2) A(31:60,1) = 18:8:10+8*30;
3) not clear

[Emerson De Souza]

Dear Oleg

thanks for your answer.

Basically, I want to generate a matrix M of TWO columns and J rows.

An initial value (=XSTART) is fixed for the first column

while the second column runs from a value

YSTART in increments K until a final value YEND .

Then an increment L is added to XSTART

and the second column runs again from

YSTART in increments K until a final value YEND.

The increment L stops if the value of X equals XEND.

For example, let

X runs in increment of 4 from 0 until 12 (XSTART=0, L=4, XEND=8)

The vector components are (0, 4, 8)

Y runs in increment of 5 from 0 until 15 (YSTART=0, K=5, YEND=15)

The vector components are (0, 5, 10, 15)

The resulting matrix should be

0 0

0 5

0 10

0 15

4 0

4 5

4 10

4 15

8 0

8 5

8 10

8 15

I hope this text clarify your doubts

and help you to find the proper sintax two

write a command that generate this matrix for given

set of initial and end values for x and y and their respective increments.

Thank you a lot

Emerson

[Oleg Komarov]

I answered your other post.