A 'Matrix Minus' Question!

There are two matrix.

A = [1 4 3 4 5
6 6 8 9 1
1 2 1 4 5
8 1 2 1 5
9 1 9 2 2
8 8 1 6 4];

B = [1 2 9 2 5];

How can I minus each row of Matrix A by B to get C? The result C =

[0  2  -6  2  0
5  4  -1  7  -4
0  0  -8  2  0
7  -1  -7  -1  0
8  -1  0  0  -3
7  6  -8  4  -1]

 I know I can do a loop. But is there an easier way? Any suggestion would be appreciated!

The loop is:

m = size(A);

for i = 1 :length(A)

      for n = 1:m(1)

          C(n,i) = A(n,i) - B(i);

      end

end

Answer 1

[the cyclist]

bsxfun(@minus,A,B)

[Xiao Tang]

Thanks man. That's exactly what I am looking for.