How do I delete a row based on the based of the first column cell?

For example. If I wanted to delete each row that contained the number 10 in the first column, how can I do that. Essentially is acts like a filter and deletes all the rows with that value.

Answer 1

[the cyclist]

If x is your array,

 x(x(:,1)==10,:) = [];

[Brady Thom]

Thank you for the speedy response! If you have a second, maybe a little description of what the notation does? I am just trying to learn and be more self sufficient

[Ryan]

x(:,1) == 10 returns a logical vector (1 for a 10, 0 otherwise). He's searching all rows (:,) and just the first column (,1).

x(logical vector,:) is locating the row's that have the 10 in the first column from before (dictated by the x(:,1) == 10) and saying select all the columns (,:) of those rows and then delete them by setting them equal to [].