Retrive cell names from structure into a string vector
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Hi
I have a structure that contains cell's inside. I would like to retrive the name of the cells into a vector, so I can make a for loop. This data is just for one year, and I have alot, where the dates change, so I cant just write the dates down since they are generated automaticly. The cell array inside each date is the same.
Dates = ['April_24_2018';'May_01_2018';'May_08_2018'... %And so on.]
for h = 1:size(Dates,1)
Data = Input.Dates(h,:){1,2}(1,1);)
end
Can't find a guide to do this, can somebody help :) ?
Best Regards Mikkel
3 Comments
Stephen23
on 12 Feb 2019
Edited: Stephen23
on 12 Feb 2019
@Mikkel: awkwardly forcing meta-data into fieldnames is not likely to make your code very neat or efficient. A non-scalar structure would make it trivially easy to loop over the elements, using basic indexing:
S(1).time = [2019,02,12];
S(1).data = {...};
S(2).time = [2019,02,12];
S(2).data = {...};
...
for k = 1:numel(S)
S(k).time
S(k).data{1}(1)
end
Accepted Answer
Adam Danz
on 12 Feb 2019
4 Comments
Steven Lord
on 12 Feb 2019
Alternately if you just want to iterate through the fields in the struct array consider using structfun.
Adam Danz
on 12 Feb 2019
Edited: Adam Danz
on 12 Feb 2019
Using a non-scalar structure would really clean things up (as suggested by Stephen Cobeldick). You could convert your existing data to this format or, if possible, you could change the existing code that generated the structure in the first place.
If you decide not to go that route, two good options are structfun at dynamic field names (as suggested by Jan and Steven Lord. If you're just applying the same function to all fields and all of your fields are organized in the same way, go with structfun(). Otherwise, go with dynamic field names (or a combination of both).
If you get stuck, feel free to follow-up. Providing a sample of data always helps.
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