NaN output is coming why?

2 views (last 30 days)
SHARAD KUMAR UPADHYAY
SHARAD KUMAR UPADHYAY on 5 Mar 2019
Commented: dpb on 5 Mar 2019
%% I am getting output as NaN, where I am using this type of program
function F_half=F_D_I(Aplus,t)
fun=@(x) (x.^(-1/2)./(exp(x-Aplus./t)+1))
F_half=integral(fun,0,inf,'ArrayValued',true,'RelTol',1e-4)
end
%%
function FT=wint(Aplus,m,Q,hh,EF,n,KB,T)
t=KB.*T./EF
muu=t.*log(exp(1./t)-1)
Aplus=@(w)APM(muu,hh,w,EF,Q)
fun=@(w)4.*EF.*Q.^2./(pi.^2.*n.*m.*KB.*T.^3).*F_D_I(Aplus(w),t).^2./sinh(hh.*w./(2.*KB.*T)).^2
FT=integral(fun,0,inf,'ArrayValued',true,'RelTol',1e-4)
end
%% when i run the program upto here then program is ok and no problem upto here.
%% but when i go as
function phi1=potential(KF,Q,L,d,e,ep,qTF)
phi1=4*pi.*e.^2./ep.*G_12(KF,Q,L,d)./((1-2*qTF.*G_11(KF,Q,L)).*(1-2*qTF.*G_11(KF,Q,L))-4*qTF.^2.*G_12(KF,Q,L,d).^2)
end
%%
function output=Main_drag(Aplus,m,Q,hh,EF,n,KB,T,KF,L,d,e,ep,qTF)
f=@(Q) 2.*KF.*Q.*potential(KF,Q,L,d,e,ep,qTF).^2.*wint(Aplus,Aminus,m,Q,hh,EF,n,KB,T)
output=integral(f,0,inf,'ArrayValued',true,'RelTol',1e-4)
end
%% to run this i use
X=Main_drag(Aplus,m,Q,hh,EF,n,KB,T,KF,L,d,e,ep,qTF)
%% I got the results in X=NaN, why please solve it.
  1 Comment
dpb
dpb on 5 Mar 2019
NaN comes from things like 0/0 and when you try to integrate [0, inf] probably your functional is something of that sort or other similar expression at extremes.
Test your anonymous function over limiting values...

Sign in to comment.

Answers (0)

Categories

Find more on Numeric Types in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!