MATLAB Answers

How to input result looping/iteret (for) to a existing matrix ?

2 views (last 30 days)
how to simple the code below with looping logic(for)? if I have Matrix A(4x4) Bu(4x1)
R=[510.5];
N=[0; 0; 0; 0];
for n = 1:6
x(n)=1650+(1100*(n-1))
end
for nn=1:6
X0=x(1,1)
X1=x(1,2)
X2=x(1,3)
X3=x(1,4)
X4=x(1,5)
X5=x(1,6)
%% Matrix Q
Q0=[760 0 0 0; 0 70 0 0; 0 0 X0 0; 0 0 0 0.001];
Q1=[760 0 0 0; 0 70 0 0; 0 0 X1 0; 0 0 0 0.001];
Q2=[760 0 0 0; 0 70 0 0; 0 0 X2 0; 0 0 0 0.001];
Q3=[760 0 0 0; 0 70 0 0; 0 0 X3 0; 0 0 0 0.001];
Q4=[760 0 0 0; 0 70 0 0; 0 0 X4 0; 0 0 0 0.001];
Q5=[760 0 0 0; 0 70 0 0; 0 0 X5 0; 0 0 0 0.001];
%% LQR calculate
[K0,S0,e0] = lqr(A,Bu,Q0,R,N);
[K1,S1,e1] = lqr(A,Bu,Q1,R,N);
[K2,S2,e2] = lqr(A,Bu,Q2,R,N);
[K3,S3,e3] = lqr(A,Bu,Q3,R,N);
[K4,S4,e4] = lqr(A,Bu,Q4,R,N);
[K5,S5,e5] = lqr(A,Bu,Q5,R,N);
%% LQR result gain
Klqr0=-K0;
Klqr1=-K1;
Klqr2=-K2;
Klqr3=-K3;
Klqr4=-K4;
Klqr5=-K5;

Accepted Answer

Pullak Barik
Pullak Barik on 25 Jun 2019
Edited: Pullak Barik on 25 Jun 2019
I can suggest the following ways-
  1. Computing Q0, Q1, ..., Q5 values in a for-loop using a single array where the values of X(i) are replaced, say Q.
  2. Use a for-loop to call lqr on each element of Q and store the result in each element of an array K.
  3. Directly negate the array K at the end instead of negating each element and storing in a new variable.
By the way, your for-loop with 'nn' as the iterating variable seems incomplete, as there is no corresponding 'end' keyword for it. Moreover, you have not used the variable 'nn' anywhere below the declaration of the for-loop, so I suggest following the 3 suggestions above and properly encapsulating your code in for-loops.
  3 Comments
irfan naufan
irfan naufan on 25 Jun 2019
how to loop in simulink ? i want to loop for any Klqr as gain and result is phi,alpha, of each gain

Sign in to comment.

More Answers (0)

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!