counting total no of particles in a bin in histogram

Hi, i have a basic problem. I had made a histogram with nbins = 100.

I want to count the number of particles of that which is maximum number of particles and display it.

what should be the best way to do it.

Thank you very much. Any help is highly appreciated.

[dpb]

Which one of the veritable multitude of binning functions now available did you use, specifically? Show us code you used.

[Ted Shultz]

Did you try looking at the counts property of the histogram object?

[Sumera Yamin]

x = randn (100,1);
n = 100;
hist (x, n);
minz = min (x);
maxz = max (x);
n_bin = (maxz-minz) / n;

% i want to locate the bin with highest number of counts and then divide total sum of that bin with n_bin.  

Answer 1

[Saurabh Kelkar]

k = hist(x,n);

gives the counts in each of the bins.

modalBin = find(k==max(k) % Gets the bin number of highest bin. Will return two bins if clashes

Alternatively i would recommend using ecdf funtion for doing this.

[Sumera Yamin]

thanks for your answer but i do not understand how can i call the no of counts of each bin?

[Saurabh Kelkar]

x = randn (100,1);
n = 10; % Using 10 bins
k = hist (x, n);
Output:
k =
     4     3     4     7    15    23    23     9     6     6

This indicates that bin 5 has 15 elements.

Alternatively using hiscounts as

histcounts(x,10) will give:
N =
     3     2     4     6    15    22    22    14     6     6
edges =
  Columns 1 through 10
   -3.2000   -2.6800   -2.1600   -1.6400   -1.1200   -0.6000   -0.0800    0.4400    0.9600    1.4800
  Column 11
    2.0000

Edges indicate that the first bin has values between -3.2 and -2.68

Hope this helps.

[dpb]

Which illustrates also a conundrum -- two functions of nominally same purpose and two different results...so which one is "right"?

All depends on the binning algorithm that TMW changed between the two.

[Ted Shultz]

It looks like hist is discouraged by mathworks...

Replace Discouraged Instances of hist and histc

[dpb]

Indeed, but there are some real advantages with them with respect to the new versions...the binning difference above being one and the ease in setting bins for certain specific uses. "Not everything new is necessarily improved."