Add a row of zeros at the end of the matrix
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Grateful for any help
x = [ 23 34 15 19]
actually i want the result to be a 4 by 2
23 0
34 0
15 0
19 0
Need to transpose x first. But unfortuantely I can't get the results.
My codes
new_A=zeros(size(x,1));
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Answers (2)
the cyclist
on 20 Sep 2019
Edited: the cyclist
on 20 Sep 2019
output = [x' zeros(4,1)];
You can generalize this a bit by using the numel function to determine and use the size of x to get the number of zeros, rather than hard-coding the number 4.
output = [x' zeros(numel(x),1)];
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Kevin Phung
on 20 Sep 2019
Edited: Kevin Phung
on 20 Sep 2019
x = [23;34;15;19];
new_x = [x zeros(size(x))]
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