Create a matrix on the basis of other matrix

Hi given a matrix

M= [ 0	4	8	6;
     0	0	0	6;
     0	0	0	6;
     2	0	0	0;
     0	0	0	0;
     0	0	0	1;
     0	4	7	0;
     5	3	0	0;
     0	0	0	6;
     0	0	0	6;];

I want to create a new matrix A that contain just the diversity, no matter of the order and with no zeros.

so in this case

A = [2 4 8 6;
     5 3 7 1];
 

Someone can help me with the code?

Answer 1

[Fabio Freschi]

Under the assumption that the "diversity" contains the same number of entries each row

for i = 1:size(M,2)
    b(:,i) = unique(nonzeros(M(:,i)));
end

If each column can have different number of interest

b = arrayfun(@(i)unique(nonzeros(M(:,i))),1:size(M,2),'UniformOutput',false)

then you can access to the unique values of the jth row as

b{j}

Answer 2

[Andrei Bobrov]

[~,j] = find(M);
C = accumarray(j,M(M ~= 0),[],@(x){unique(x,'stable')})
if all(diff(cellfun(@numel,C)) == 0)
    C = [C{:}];
end