how can i find the intersection point between the two curves and the minimum point to the other curve?

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k1=10^-4;k2=2*10^5
k2 = 200000
d=0.08;
a=50*10^-6:1*10^-6:100*10^-6;
cr =k1./a;
cf =k2*d.*a;
ctot =cr+cf;
plot(a,cr,a,cf,a,ctot)
title('optimal')
xlabel('cross section area')
ylabel('costs')
legend('cr','ctot','cf')
0001 Screenshot.png

Accepted Answer

Image Analyst
Image Analyst on 26 Oct 2019
Do you want the (harder) analytical answer (like from the formula) or the (easier) digital answer from the digitized vectors, like
distances = abs(cf-cr)
[minDistance, indexAtMin] = min(distances);
y1AtMin = cf(indexAtMin)
y2AtMin = cr(indexAtMin)
aAtMin = a(indexAtMin)
hold on;
line([aAtMin, aAtMin], ylim);
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More Answers (1)

mohamed asran
mohamed asran on 9 Nov 2020
clc
clear all
r=0.05;
l=0.01;
st=0.0001;
v=220;
Kf=18;
j=3;
Tl=60;
i=0;
w=0;
I=[];
W=[];
t=[];
for dt=0:0.0001:1
I=[I i];
t=[t dt];
W=[W w];
i=i+(((v-r*i)-(Kf*w)/l)*st);
w=w+((((Kf*i)-Tl)/j)*st);
end
plot(t,W,'linewidth',4)
xlabel('time (sec)','fontsize','18','fontweight','b');
ylabel('SPEED (rpm)','fontsize','22','fontweight','b');
title('Dynamic model of separately excited dc motor under constant excitation');
axis([0 0.1 0.5])
gri;d
plot(t,I,'linewidth',4)
xlabel('time (sec)','fontsize','18','fontweight','b');
ylabel('current (A)','fontsize','22','fontweight','b');
title('current response of rl circuit');
axis([0 0.1 0.5])

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