# sort a string based on particular value

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Sajid Afaque on 19 Mar 2020
Edited: Sriram Tadavarty on 19 Mar 2020
Hello All,
i have a list of type
ch = { 'temp_25_vgs_8', 'temp_25_vgs_3', 'temp_25_vgs_9', 'temp_25_vgs_10', 'temp_20_vgs_8', 'temp_20_vgs_5', 'temp_25_vgs_5'};
i need to sort it based on vgs value (or both vgs and temp) and get back the list as
ch = { 'temp_20_vgs_5',
'temp_20_vgs_8',
'temp_25_vgs_3',
'temp_25_vgs_5',
'temp_25_vgs_8',
'temp_25_vgs_9',
'temp_25_vgs_10'
} ;

Sriram Tadavarty on 19 Mar 2020
Edited: Sriram Tadavarty on 19 Mar 2020
Hi Sajid,
The sort function with the arrayfun can be used to check this.
chs = arrayfun(@(x) str2double(string([ch{x}(5+1:8-1) ch{x}(13:end)])),1:numel(ch))
[~,i] = sort(chs);
out = ch(i);
Hope this helps.
Regards,
Sriram

Sajid Afaque on 19 Mar 2020
Hello Sriram,
it is only taking temp into consideration.
i need it to get sort based on vgs value also
K
K>> sort(ch)'
ans =
'temp_20_vgs_5'
'temp_20_vgs_8'
'temp_25_vgs_10'
'temp_25_vgs_3'
'temp_25_vgs_5'
'temp_25_vgs_8'
'temp_25_vgs_9'
Sriram Tadavarty on 19 Mar 2020
Hi Sajid,
Here is what you are looking for, if you know what the index locations are already, then you perform something as such:
chs = arrayfun(@(x) str2double(string([ch{x}(5+1:8-1) ch{x}(13:end)])),1:numel(ch))
[~,i] = sort(chs);
out = ch(i);
To find the locations exactly which has the starting numbers, you can use this
ind = regexp(ch,'_'); % it provides index in each cell
Let me know if this helped.
Thanking you.
Regards,
Sriram