How to compute the derivative of the neural network?
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Hi,
Once you have trained a neural network, is it possible to obtain a derivative of it? I have a neural network "net" in a structure. I would like to know if there is a routine that will provide the derivatives of net (derivative of its outputs with respect to its inputs).
It is probably not difficult, for a feedforward model, there is just matrix multiplications and sigmoid functions, but it would be nice to have a routine that will do that directly on "net".
Thanks!
Accepted Answer
More Answers (4)
Filipe
on 20 Oct 2012
0 votes
1 Comment
Greg Heath
on 24 Oct 2012
You can try to make life easier by doing the pre and postprocessign yourself before and after training.
trevor
on 7 Nov 2013
0 votes
Hi Filipe,
Could you possibly share your code for computing the partial derivative of the ANN, or provide some info on the steps you used? That would be immensely useful!
Thanks, Trevor
Muhammad Saif ur Rehman
on 5 Apr 2019
0 votes
Hi Filipe,
Can you share your code for computing the partial derivative of defined cost function w.r.t input?
Regards Saif
soo-choon kang
on 14 Aug 2021
0 votes
net1 = fitnet(3);
net1 = train(net1,x',y');
% normalize x
nx = (x-net1.input.processSettings{1,1}.xmin)*net1.input.processSettings{1,1}.gain+net1.input.processSettings{1,1}.ymin;
h = tanh(net1.b{1}+net1.IW{1}*nx'); % h = [3xn] IW{1} = [3x1] x' = [1xn]
ny = net1.b{2}+net1.LW{2,1}*h; % y = [1xn] LW{2,1} = [1x3]
% de-normalize y
ypredict = (ny-net1.output.processSettings{1,1}.ymin)/net1.output.processSettings{1,1}.gain+net1.output.processSettings{1,1}.xmin;
% above ypredict is equivalent to predict(net1,x)
% derivative of nn at normalized scale
dnydnx = sum(net1.LW{2,1}'.*net1.IW{1}.*(1-h.*h),1)'; % dyy = [1xn] h'*h = [nxn]
% derivative of nn at real scale
dydx = dnydnx*net1.input.processSettings{1,1}.gain/net1.output.processSettings{1,1}.gain;
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