Solution of an Implicit Function

Hello,
I have an equation which is (200)*(2-0.1*sqrt(x)-2*log(2-0.1*sqrt(x)))-(200)*(2-0.1*sqrt(100)-2*ln(2-0.1*sqrt(100)))=t. I am supposed to find x value for t=1000, but I could not achieve. Can you help me on this?
Thank you

1 Comment

Use "fzero" to solve your equation for x, given t = 1000.

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Answers (1)

Ameer Hamza
Ameer Hamza on 29 Mar 2020
Edited: Ameer Hamza on 29 Mar 2020
There is no function 'ln' in MATLAB. I guess you meant log to the base e. Try this
f = @(x,t) (200)*(2-0.1*sqrt(x)-2*log(2-0.1*sqrt(x)))-(200)*(2-0.1*sqrt(100)-2*log(2-0.1*sqrt(100))) - t;
f_sol = fsolve(@(x) f(x, 1000), 0);
I suspect that by log you might have meant log to the base 10. In that case replace first log with log10
f = @(x,t) (200)*(2-0.1*sqrt(x)-2*log10(2-0.1*sqrt(x)))-(200)*(2-0.1*sqrt(100)-2*log(2-0.1*sqrt(100))) - t;
f_sol = fsolve(@(x) f(x, 1000), 0);

2 Comments

Sorry, I meant log as natural logarithm, you're right.
I really stacked and this worked perfectly, thank you.
Glad to be of help.

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R2017b

Asked:

on 29 Mar 2020

Commented:

on 29 Mar 2020

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