1 view (last 30 days)
mmmm on 23 Apr 2020
Commented: Rena Berman on 14 May 2020
Matlab function, v(x) value if input count is x? E = 70 Gpa, I= 1.7 x 10^-6 m^4, q= 2.7 kN/m, L= 6.25 m
v(x) = (gx/24EI)* (L^3 - 2Lx^2 + x^3)

Walter Roberson on 23 Apr 2020
is the question how to find x given v(x)? The equation is degree 4 so there would be four solutions.
Walter Roberson on 23 Apr 2020
so first test whether x is within range. if it is then use the formula. Just remember that matlab does not have any implied multiplication: gx does not mean g multiplied by x
Rena Berman on 14 May 2020

BALAJI KARTHEEK on 23 Apr 2020
Edited: BALAJI KARTHEEK on 23 Apr 2020
function v=v(x)
E = 70;
I= 1.7*1e-6;
q= 2.7;
L= 6.25;
if x>=0
if x<=L
v = ((g*x)/(24*E*I))*((L^3)-2*L*(x^2)+(x^3));
else
v=[];
end
else
v=[];
end

Walter Roberson on 23 Apr 2020
Notice that they have already deleted the part that shows the question to be answered. There is the distinct appearance that what they may have learned from this is that they can post homework assignments without putting any effort into solving the problem, wait for someone to answer, and then hide the evidence that it was homework.
Walter Roberson on 23 Apr 2020
and now they have removed nearly all of the rest of the question, having received effectively free private consulting from you and not having to put in any thought of their own to the solution.
If you had provided guidance about the meaning of parts of code and about syntax, but only given them ideas and outline, then perhaps they would still have edited away the question, but they would have had to think for themselves about the solution and so would have learned something.
We try to help people learn about matlab by working through ideas with them but leaving them to put the ideas together.
Stephen Cobeldick on 23 Apr 2020
Original question by miika k recovered from Google Cache:
Matlab function, v(x) value if input count is x? E = 70 Gpa, I= 1.7 x 10^-6 m^4, q= 2.7 kN/m, L= 6.25 m
v(x) = (gx/24EI)* (L^3 - 2Lx^2 + x^3)

R2020a

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!