Help with iteration problem
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>> x=0.7; % x is fixed value
>> syms s % s is symbols
>> v=char(x./(s^2+1)); % v is function of (x,s)
% numerical method to compute inversion Laplace transformation
% this function is available through remark at below
>> [t1,ft1]=INVLAP(v,0.0001,5,1000,6,39,89);
>> plot(t1,ft1)
please, help me the previous small code run easily, but i need (x not equal fixed), i.e., i need x- run over the interval (0:0.1:1), and also make all the following steps, then make 3-D figures between mesh(x,t1,ft1)
% remark
% INVLAP Numerical Inversion of Laplace Transforms
Answers (1)
bym
on 19 Nov 2012
seems like a simple 'for loop' would do the trick
x = 0:.1:1;
for x
v=char(x./(s^2+1)); % v is function of (x,s)
% modify call to INVLAP to store ft1 in a matrix
...
end
mesh(...)
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