longest wet and dry spell of the matrix

I have the following matrix a=

[99  99  0.100  0.120  0  0.500  0;

0       0  0       0       0.150   0.120   0;

0.110  0.010  0.010  0  0  0.300  0.100;

0  0.250  0  0.050  0.060  0.100  0.110;

0  0.120  0.040  0  0.500  0.750  99];

I want to find the longest wet and dry spell of the matrix of each row ( the longest days in a row that it rained and it did not rain)...

   I have   
i=1;1:5
d=(a(i,:)~=0 & a(i,:)<99) 
the 1's form the answer tell me how many days in a row did rain but I don't know how to make a code that will return which week had the  longest days in a row that it rained and it did not rain

Answer 1

[Image Analyst]

Once again, this is a situation that would be trivial if you had the Image Processing Toolbox because in one line of code you can find the lengths of all non-zero stretches of rainfall for a column. One more line of code would tell you the longest of those stretches. Do you have that toolbox? Type ver to find out. If you do, try this code:

a=[99  99  0.100  0.120  0  0.500  0;
0       0  0       0       0.150   0.120   0;
0.110  0.010  0.010  0  0  0.300  0.100;
0  0.250  0  0.050  0.060  0.100  0.110;
0  0.120  0.040  0  0.500  0.750  99]
[rows columns] = size(a);
for row = 1 : rows
  measurements = regionprops(a(row, :)< 99 & a(row, :) > 0, 'Area');
  % Get all the stretches of rain
  allRains = [measurements.Area]
  % Get the longest rain.
  longestStretch = max(allRains);
  fprintf('For row %d, the longest stretch with rain = %d.\n\n', ...
    row, longestStretch);
end

In the command window:

allRains =
     2     1
For row 1, the longest stretch with rain = 2.

allRains =
     2
For row 2, the longest stretch with rain = 2.

allRains =
     3     2
For row 3, the longest stretch with rain = 3.

allRains =
     1     4
For row 4, the longest stretch with rain = 4.

allRains =
     2     2
For row 5, the longest stretch with rain = 2.

[marie]

yes, I have it

[marie]

Thank you!

[Image Analyst]

You're welcome, but, well, did it work? If so, mark it as "Answered".