Is there any other ways instead of using for loop for this one?

A={[10,11,10,7],[7,8,7,6],[11,10,9,9],[7,5,11,5];[9,8,6,11],[10,6,9,7],[6,12,8,9],[7,10,12,9];[10,7,12,6],[8,11,7,5],[8,5,9,9],[10,10,10,10]};
C=[1	1	0	1;0	1	1	1;1	0	1	1; 0	1	1	0];
[a,b]=find(~C);
for i=1:numel(a)
    for j=1:size(A,1)
        A{j,a(i)}(b(i))=100;       
    end
end

Is there any other smart ways to solve?

Answer 1

[Matt J]

It would be better if A were just a 3D numeric array,

Amat=cell2mat(reshape(A, size(A,1),1,[]))

Then you could simply do,

Amat(:,~C.')=100

[SM]

Is it possible to get back from 3D numeric array to celll?

[Matt J]

Yes, use num2cell().