how can I make in Simulink ∫ dt?

Hi, how can I make in Simulink ∫ dt? In time domain, not Laplace domain.
Thank you:)

Answers (1)

Andreas Goser
Andreas Goser on 14 Dec 2012
Edited: Andreas Goser on 14 Dec 2012
The whole concept of Simulink is time based simulation. You might be confused by the look of the blocks and the transfer functions are displayed like 1/s or 1/s-1 etc.
So just use the integrator block and you are fine.

5 Comments

I know that I can use 1/s but my teacher told me to not use 1/s. He said to me that I can find ∫ dt in Simulink Lybrary Browser. I have to simulate a DC motor. And one of blocks is (1/La)*∫ dt. Where La is known. Could you help me please?:)
I can't help with that. I can only speculate what your teacher might think. There are blocks that display the integral symbol, like the "Integrator Limited" block. You need to ask the teacher.
I asked today him and I can remember that he told me that I can replace 1/s with a MUX+I can't remember what other blocks. It's that possible?
I do not see any relationship between an integral operation and a signal infrastructure block. This is very confusing. Probably both of you call into Technical Support to sort out things together?
I spoke with my teacher and I'll use the 1/s block. Thank you very much for you support.

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on 14 Dec 2012

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