eleminating data from a long vector
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Hi all!
i have an index vector:
%
index=[id1;id2;id3.....idn]
and i have a long vector: A
i want to eleminate the elment of the vector a which have the index in index in this way:
%
A(id1:id1+30)=[]
A(id2:id2+30)=[]
.
.
.A(idn:idn+30)=[]
how could i write this in matlab in a compact manner?
thank you
1 Comment
Walter Roberson
on 19 Feb 2013
Are you certain this is what you want to do? After the first removal, everything from id1+30 onward in the vector would "fall down" 31 places. Does id2 take that renumbering into account?
Accepted Answer
Azzi Abdelmalek
on 19 Feb 2013
Edited: Azzi Abdelmalek
on 19 Feb 2013
A=rand(1,1000); % Example
index=[10 100 500]
idx=arrayfun(@(x) x:x+30,index,'un',0);
A(cell2mat(idx))=[]
2 Comments
Walter Roberson
on 19 Feb 2013
This is not equivalent to the original sequence in that the original sequence does not delete id2:id2+30 until after id1:id1+30 are gone, so in absolute locations it might need to add 31 more for the 2nd index, 62 for the 3rd, and so on... depending on the sort order of the indices.
Azzi Abdelmalek
on 19 Feb 2013
Edited: Azzi Abdelmalek
on 19 Feb 2013
I don't think that what he meant by the sequence. I guess he want to remove them at the same time.
More Answers (1)
Andrei Bobrov
on 19 Feb 2013
A=1:1000; % Example
index=[10 100 500];
n = 30;
A(bsxfun(@plus,index,(0:n-1)'))=[];
3 Comments
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