datevec back to regular time
8 views (last 30 days)
Show older comments
Jo Bremer Balestracci
on 9 Nov 2020
Commented: Walter Roberson
on 9 Nov 2020
I am using datevec and performing calulations. The end result needs to be converted back to a regular time for the user. I have tried different things and I am still am getting the result I want. I did not put a date in which I normally do using the Date Picker. Can you help me?
t=datevec(state.TimeHHMMssEditField); % where state.TimeHHMMssEditField = 1:31:00
desiredTime = t(4) *3600 + t(5) * 60 + t(6);
NewTime =desiredTime % 5460
StartTime = NewTime + .5 %5460.5
Duration = (state.DurationinsecondsEditField)' % where state.DurationinsecondsEditField = 30 seconds
EndTime = StartTime + Duration %5490.5
% EndTime is in seconds. I want to convert the EndTime (5490.5) to look like 1:31:35
How do I do this?
0 Comments
Accepted Answer
Walter Roberson
on 9 Nov 2020
datestr(EndTime/(3600*24),'HH:MM:ss')
However, this will have leading 0 . Leading 0 is used automatically if you do not use AM indicator.
I would recommend, by the way, that you switch to using datetime and duration objects, which make the code a lot cleaner.
5 Comments
Walter Roberson
on 9 Nov 2020
'HH:MM:ss.ff' for serial datenum work.
'HH:mm:ss.SS' for datetime() work.
More Answers (1)
Steven Lord
on 9 Nov 2020
I second Walter Roberson's suggestion to skip the datevec form and to use duration.
t = '1:31:00'
du = duration(t)
newtime = du + seconds(0.5)
newtime.Format = 'hh:mm:ss.SSS' % Show fractional seconds
newt = string(newtime) % or char(newtime)
0 Comments
See Also
Categories
Find more on Time Series Objects in Help Center and File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!