Distance Matrix Without Loop

Hi all,

I would like to get a matrix A that for each aij, I'd get the distance (i.e. abs(x-y)) between the i and j values in the following manner:

x = [3, 5, 10];

y = [3, 5, 10]; % those are the locations in x and y, they are the same

Desired Matrix:

A = [0 2 7

2 0 5

7 5 0];

Please notice it's normal abs(x-y) and not the euclidean distance as technically both x and y are on the same axis.

I do know I can do a for loop to achieve this, but I might have a very large matrix and I was wondering if a quicker way is possible.

Thanks!

Answer 1

[Matt J]

x = [3, 5, 10];
y = [3, 5, 10];

A = abs(x(:)-y(:).')

A = 3×3

0 2 7 2 0 5 7 5 0