or() in categorical variable

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TAEKYU EOM
TAEKYU EOM on 23 Nov 2020
Commented: TAEKYU EOM on 23 Nov 2020
I don't know why the results of index1 and index2 are different.
The variable
financial_status=[1,2,3,4,5];
index1 = find(financial_status==or(1,2));
index2 = find(financial_status>=1&financial_status<=2);
  2 Comments
dpb
dpb on 23 Nov 2020
Because
>> or(1,2)
ans =
logical
1
>>
TAEKYU EOM
TAEKYU EOM on 23 Nov 2020
I got it, thanks!

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Accepted Answer

dpb
dpb on 23 Nov 2020
Because
>> or(1,2)
ans =
logical
1
>>
You're apparently looking for
>> ismember(financial_status,[1,2])
ans =
1×5 logical array
1 1 0 0 0
>>
Rarely are the actual indices returned by find needed, but can be if this is one of those cases that simply using the logical addressing array isn't sufficient.

More Answers (1)

Walter Roberson
Walter Roberson on 23 Nov 2020
Edited: Walter Roberson on 23 Nov 2020
ismember(financial_status, 1:2)
At the moment I cannot think of any computer language that expresses a set membership test in terms of an equality test. Which computer language were you inspired by?

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