Index in Position 1

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BoostedMan
BoostedMan on 1 Dec 2020
Answered: VBBV on 1 Dec 2020
It keeps saying Index in position 1 exceeds array bounds (Must not exceed 1)
I am fairly new to matlab but I think its saying some value is 0, I am looking for a 4x4 matrix, I have gotten 4x3, but now it only gives me that error and im not sure where I am going wrong.
  3 Comments
BoostedMan
BoostedMan on 1 Dec 2020
How would I change this in order to get zero's above the diagonal in the A matrix?
Walter Roberson
Walter Roberson on 1 Dec 2020
A = zeros(n-1, n);

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Accepted Answer

VBBV
VBBV on 1 Dec 2020
%Lab 8
%Jack Philibotte
%--------------------
%Polynomial Interpolation
x= [15, 20, 25, 30];
y= [1476.77, 1482.19, 1496.69, 1509.28];
%------------
n=length(x);
A = ones(4,4);
for k= 1:n-1
for kk=2:n
A(k,kk)= (x(k)-x(1))*A(k,kk-1);
end
end
disp(A)
>>

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