Elegant / Vectorized way of getting array from start_index vector and end_index vector?

Hello

Suppose start_index = [1 5 10]; and end_index = [3 8 12];

Is there an elegant solution to get an output of [1 2 3 5 6 7 8 10 11 12], that is the function takes each start value and gives all inclusive values between the start and end value, repeats with the next index, until all inclusive values are included in a single output vector?

Thank you

Answer 1

[Azzi Abdelmalek]

EDIT

v=[1 2 3 5 6 7 8 10 11 12]
start_index = [1 5 10]; 
end_index = [3 8 12];
out=cell2mat(arrayfun(@(x,y) x:y,start_index, end_index,'un',0))
out=intersect(out,v)

[Evan]

Lines 2~4 were what I needed. Brilliant, exactly what I was looking for. Thanks! :)

Answer 2

[Jan]

start_index = [1 5 10];
end_index   = [3 8 12];

index(end_index + 1) = -1;  % Implicit pre-allocation
index(start_index)   = 1;
result               = find(cumsum(index));

In many cases logical indexing is more efficient:

result = (cumsum(index(1:end-1)) == 1);

An even more efficient method is FEX: mcolon.

[Azzi Abdelmalek]

Nice solution