Input [Hex] String then convert to binary from Hex
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How can I convert this string [0,1,2,3,4,5,6,7,8,9,0xA,0xB] binary?
Hex inputs are:
0xA = 10
0xB = 11
My Goal is to get one long consecutive binary output to look like this:
change it decimal, then to binary, then combine all binary values
'0000 0001 0010 00010'
but with no spaces and continous. Basically make it into a 32bit vector
'00000001001000010'
I have tried this code:
Array = [0,1,2,3,4,5,6,7,8,9,0xa,0xb];
reshape(dec2bin(Array),1,[])
reshape(dec2bin(Array,8),1,[])
I get this Error:
>> untitled4
Error: File: untitled4.m Line: 1 Column: 31
Invalid expression. Check for missing multiplication operator, missing or unbalanced delimiters, or other syntax
error. To construct matrices, use brackets instead of parentheses.
1 Comment
Rik
on 15 Dec 2020
Array = [0,1,2,3,4,5,6,7,8,9,0xa,0xb];
reshape(dec2bin(Array),1,[])
reshape(dec2bin(Array,8),1,[])
As you can see, your code runs in R2020b. I just tested on my own copy of R2020a, and it works there as well.
Also a side note: Array is not a string, it is not even a char, it is a uint8 array (which dec2bin probably converts to double internally).
Answers (1)
Jan
on 15 Dec 2020
I guess, you are using an older version of Matlab, which does not allow to write hex numbers in the code directly. Then:
HexArray = {'0','1','2','3','4','5','6','7','8','9','a','b'};
DecArray = hex2dec(HexArray);
reshape(dec2bin(DecArray),1,[])
reshape(dec2bin(DecArray,8),1,[])
2 Comments
Rik
on 15 Dec 2020
I thought that as well, but this OP actually did what many didn't: marking the release they use. As that is R2020a, the original code should work as well.
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