# Move multiple rows without swapping

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Rishi Balasubramanian on 23 Dec 2020
Hello,
I have a mxn matrix of binary data. I want to write a code where I find the rows in column n which have 1s in them and move them to bottom of the row. I want a generalised code for this as it will be in a loop where multiple iterations of this will be executed.
%For example, assume this is my matrix
% a b c d e f g h i j k l
H = [0 0 1 1 0 1 0 1 0 1 1 0; %1
0 0 0 1 0 1 1 0 1 0 1 0; %2
0 1 1 0 0 1 1 1 0 0 0 1; %3
0 1 1 0 1 0 1 0 1 0 0 1; %4
0 0 0 1 1 0 0 1 1 0 0 0; %5
0 1 0 0 1 0 0 0 0 0 1 0]; %6
%In column 'l' there are 2 rows with 1s in them (row 3 and 4).
% I want to move rows 3 and 4 to the bottom. My final matrix should look like this.
% a b c d e f g h i j k l
H = [0 0 1 1 0 1 0 1 0 1 1 0; %1
0 0 0 1 0 1 1 0 1 0 1 0; %2
0 0 0 1 1 0 0 1 1 0 0 0; %5
0 1 0 0 1 0 0 0 0 0 1 0; %6
0 1 1 0 0 1 1 1 0 0 0 1; %3
0 1 1 0 1 0 1 0 1 0 0 1]; %4
%Any help is appreciated. I thank in advance.

Ive J on 23 Dec 2020
H = randi([0 1], 6, 10)
H =
0 1 0 1 1 0 0 0 1 0
1 1 1 0 1 1 0 1 1 1
0 0 0 0 1 0 0 1 0 1
1 1 0 0 1 1 1 0 0 1
1 1 0 0 1 1 1 1 0 0
1 0 1 1 1 1 1 0 1 1
col = 9;
H = [H(H(:, col) < 1, :); H(H(:, col) > 0, :)]
0 0 0 0 1 0 0 1 0 1
1 1 0 0 1 1 1 0 0 1
1 1 0 0 1 1 1 1 0 0
0 1 0 1 1 0 0 0 1 0
1 1 1 0 1 1 0 1 1 1
1 0 1 1 1 1 1 0 1 1
Rishi Balasubramanian on 23 Dec 2020
Hello, One more question. Hopefully its the last. Say I want to move a single row to a specific postion? How do I do that?
For ex
% a b c d e f g h i j k l
H = [0 0 1 1 0 1 0 1 0 1 1 0; %1
0 0 0 1 0 1 1 0 1 0 1 0; %2
0 1 1 0 0 1 1 1 0 0 0 1; %3
0 1 1 0 1 0 1 0 1 0 0 1; %4
0 0 0 1 1 0 0 1 1 0 0 0; %5
0 1 0 0 1 0 0 0 0 0 1 0]; %6
% I want to move row 2 to row index 5 such that my final matrix is -
% a b c d e f g h i j k l
H = [0 0 1 1 0 1 0 1 0 1 1 0; %1
0 1 1 0 0 1 1 1 0 0 0 1; %3
0 1 1 0 1 0 1 0 1 0 0 1; %4
0 0 0 1 1 0 0 1 1 0 0 0; %5
0 0 0 1 0 1 1 0 1 0 1 0; %2
0 1 0 0 1 0 0 0 0 0 1 0]; %6