Multiplying each number in a matrix by a row

I have a matrix A and i want each value in a row to the order of a row B. Then, the sum of all these values entered back into the same place as the number in A.

eg

A = [1 2 3 4 5; 6 7 8 9 10; 11 12 13 14 15]

B = [1; 2; 3; 4; 5; 6]

therefore sum(A(1,1).^B) back into A(1,1).

Any idea how i can do this?

Please help. Thanks

Answer 1

[Youssef Khmou]

hi, you can try :

 % Your data
 A = [1 2 3 4 5; 6 7 8 9 10; 11 12 13 14 15];
 B = [1; 2; 3; 4; 5; 6];

 % Cell
 C=cell(size(A));
 for x=1:3
 for y=1:5
 C{x,y}=kron(A(x,y),B);
 end
 end

 % Summation :
 G=cell(size(C));
 for x=1:3
 for y=1:5
 G{x,y}=sum(C{x,y});
 end
 end
 G=cell2mat(G);

[Jessica Parry]

thanks but im affraid this produces the error;

Conversion to cell from double is not possible.

Error in Untitled5 (line 9) C(x,y)=kron(A(x,y),B);

[Youssef Khmou]

i corrected that error its simple change from () to {} because its a cell

The code works fine