call variable from next function

Hi, im confused when i have a variable described in the second function, but recently i need the variable to used in first function. How can I do this? Anyone help me please.

This is my firts function, here i need the value of variabel B:

function cylindrical
%Parameter ellipsoid WGS84
a= 6378137;
b= 6356752.3;
E =((a^2)-(b^2))/(a^2);
N=a./(sqrt(1-((E^2)*(sin(deg2rad(B)).^2))));
M=a.*(1-(E^2))./((1-(E^2)*(sin(deg2rad(B).^2))).^(2/3));
%
%  Tissot distortion ellipses (indicatrix)
jacobi=['d',projection];
dphi=30;dlam=30;                             % Spacing between parallels and meridians for Tissot ellipses
phi=-60:dphi:60;
lam=-180+dlam:dlam:180-dlam;
for i=1:length(phi)
   Phi=phi(i);
   G=[(N^2)*(cos(deg2rad(B))^2),0;0,(M^2)];        % Metric (matrix) of the ellipsoid (Radius = 1)
   for j=1:length(lam)
      J=feval(jacobi,Phi,lam(j));          % Jacobian matrix of the mapping equations
      C=J'*g*J;                              % based on unit metric (matrix) of the chart: g=eye(2)
   end
   

Here my second function that describe the variabel B:

   function [x,y]=cylindrical(B,L,const)
       n < 2
   error('Cylindrical needs at least two arguments');
end
if nargin == 3
   R=const;
else
%Parameter WGS84
a= 6378137;
b= 6356752.3;
E =((a^2)-(b^2))/(a^2);
N=a./(sqrt(1-((E^2)*(sin(deg2rad(B)).^2))));
M=a.*(1-(E^2))./((1-(E^2)*(sin(deg2rad(B).^2))).^(2/3));
end
%
B=B(:);L=L(:);
if length(B) ~= length(L)
   [L,B]=meshgrid(L,B);
end

[KALYAN ACHARJYA]

You have to call the second function (From the main script) by passing inputs, B,L and const, which evaluates the x and y values

[Adam Danz]

You can't have two functions with the same name.

Secondly, B is both an input and an internal variable that overwrites the input. That makes no sense.

Lastly, the final definition of B is [L,B]=meshgrid(L,B); which uses L and B which are both inputs so this can be computed outside of the function.