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How do I find the indices of NaN values in a cell array?

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Cai Chin
Cai Chin on 16 Jan 2021
Commented: Walter Roberson on 17 Jan 2021
Hi, I have a 3390 x 1 cell array containing 4 x 30 doubles. Some of these doubles contain NaN values which I would like to replace by the preceding double. How do I detect the indices of the doubles containing 'NaN' values and then replace them with the preceding 4x30 double? I have attached the cell array in question. Thanks in advance.

Accepted Answer

Star Strider
Star Strider on 16 Jan 2021
Try this:
D = load('XTrain2_all.mat');
XTrain2_all = D.XTrain2_all;
hasNaN = cellfun(@nnz,cellfun(@isnan, XTrain2_all, 'Unif',0), 'Unif',0); % Cells With ‘NaN’ Values
idx = find([hasNaN{:}]); % Their Indices
XTrain2_all(idx) = XTrain2_all(idx-1); % Replace With Previous
hasNaN = cellfun(@nnz,cellfun(@isnan, XTrain2_all, 'Unif',0), 'Unif',0); % Check
Check = find([hasNaN{:}]); % Check
.
  8 Comments
Star Strider
Star Strider on 17 Jan 2021
My pleasure!
It is a possibility that there will be consecutive missing blocks, so is there any way of essentially scanning through the indices until the last non-NaN index is found and then replacing all the missing blocks with this?
That would likely require looping through the ‘idx’ values. The first ‘idx’ value would be replaced with the matrix preceeding it, and the subsequent ‘idx’ values as well. It could end up that for consecutive ‘idx’ values, the same matrix could be duplicated consecutively as the result.
Also, if there are multiple missing blocks from the first inde onwards, is it possible to scan forwards and replace the missing indices with the next non-NaN index values?
That would likely require indexing in reverse, starting with the first full (non-NaN) cell matrix and going backwards. I have no idea how you would want to treat the rest of the array, whether going backwards from the last ‘idx’ value to the first would work, or if you would want to treat the various segments of the cell array differently.
In any event, all those possibilities would likely require a loop of some sort.
.

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More Answers (1)

Walter Roberson
Walter Roberson on 16 Jan 2021
The below accounts for the possibility of multiple nan blocks.
It does not, however, account for the possibility that the first block is nan (there is no previous block to fill from in that case.)
hasnan = cellfun(@(C) any(isnan(C(:))), XTrain2_all);
idx = 1 : length(C);
idx(hasnan) = 1;
idx = fillmissing(idx, 'previous');
newC = C(idx);
  2 Comments
Walter Roberson
Walter Roberson on 17 Jan 2021
To also account for the possibility of the first block being nan:
load XTrain2_all.mat
hasnan = cellfun(@(C) any(isnan(C(:))), XTrain2_all);
idx = 1 : length(XTrain2_all);
idx(hasnan) = nan;
idx = fillmissing(fillmissing(idx, 'previous'),'next');
newXTrain2_all = XTrain2_all(idx);

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