how to extract the bounding box area as segmented object from video frame?...I have been trying imcrop but the rectangle cropped out is not as same as bbox rectangle.

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I am using computer vision toolbox.. this is the code..Is there any other way of doing it??
please help..thankyou in advance!
crop=bbox(:,); % all bbox that hav objects
crop=transpose(crop); % bbox as crop in row major as for rectangles
num = size(crop,1);
for k = 1: num
crop(k,2)=crop(k,2)-crop(k,3); % ymin is required but ymax is in upper left corner
temp=crop(k,3); % swapping height and width as required in rectangle! crop(k,3)=crop(k,4); crop(k,4)=temp;
[Xtest,Ytest,itest,Rtest]=imcrop(image,crop(k,:));
imshow(itest);

Accepted Answer

Image Analyst
Image Analyst on 24 Apr 2013
I don't know what bbox is. Don't use image as the name of your image variable because it's the name of a built-in function. Simply crop like this:
croppedImage = imcrop(fullImage, [leftColumn, topRow, numberOfColumns, numberOfRows]);
You have to figure out how to get leftColumn, topRow, numberOfColumns, numberOfRows.
  2 Comments
sania
sania on 29 Apr 2013
Thankyou for the reply..actually m using computer vision system toolbox..After doing blol analysis I got bounding box for the object which is the vehicle in the frames.. This bbox is actually the same bounding box.This is the code..
hblob = vision.BlobAnalysis( ... 'CentroidOutputPort', false, ... 'AreaOutputPort', true, ... 'BoundingBoxOutputPort', true, ... 'OutputDataType', 'single', ... 'NumBlobsOutputPort', false, ... 'MinimumBlobAreaSource', 'Property', ... 'MinimumBlobArea', 250, ... 'MaximumBlobAreaSource', 'Property', ... 'MaximumBlobArea', 3600, ... 'FillValues', -1, ... 'MaximumCount', 80);
[area, bbox] = step(hblob, fg_image);
So the left column, toprow, no of columns, number of rows that you have told to find to use imcrop is sctually given by this bbox!
But still m not getting the segmented vehicle..The box is drwan correctly but not segmented via imcrop..I think the cordinates are not matching for bbox and imcrop..Please please help..
Image Analyst
Image Analyst on 29 Apr 2013
I don't know what step() does, but in all the MATLAB functions that I can think of when it wants a rectangle, it's [xStart, yStart, xSize, ySize]. Check with the documentation for step() - for example make sure it's not using row, column instead of x,y.

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More Answers (1)

Anand
Anand on 29 Apr 2013
It seems to work for me...The rectangle specification provided by the vision.BlobAnalysis object is the same as that required by imcrop.
im = padarray(strel('disk',100,0).getnhood,[50 25],'pre');
hblob = vision.BlobAnalysis;
[area,centroid,bbox] = step(hblob,im);
>> bbox
bbox =
26 51 201 201
out = imcrop(im,bbox);
imshow(out);
  2 Comments
sania
sania on 29 Apr 2013
running the same code giving me this error:
Error using ==> imageDisplayParsePVPairs at 121
Invalid input arguments.
Error in ==> imageDisplayParseInputs at 70 [common_args,specific_args] = imageDisplayParsePVPairs(varargin{:});
Error in ==> imshow at 199 [common_args,specific_args] = ...
Error in ==> imcrop>parseInputs at 248 imshow(a,cm);
Error in ==> imcrop at 94 [x,y,a,cm,spatial_rect,h_image,placement_cancelled] = parseInputs(varargin{:});

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