How to make a single array of values from multiple different arrays one after the other

Hello!

I have one array, A, with serial dates from a range of dates and the same time for each date, so like for every day of one month in one year at 1:30 AM. I have another array, B, with serial dates of that same date range from that same month and year at a different time but all at 4:30 PM instead. I have another array C, with the same date range but at 11:30 pm. I want to combine all these arrays into one so that they are one large array with the dates and times in order which would be one value from A then another from B, then the next from C, then the next from A, and so on like A B C A B C A B C...

Sorry if this was unclear, thank you!

[David Hill]

Recommend providing a sample of your arrays. Recommend converting using datenum().

[Claire]

Here is a sample of my arrays:

A B C

736055.063 736055.521 736055.896

736056.063 736056.521 736056.896

736057.063 736057.521 736057.896

I would like to combine them into one array that would look something like this:

Full array (serial date from A, followed by serial date from B, followed by serial date from C, on repeat until it is the length of the 3 arrays combined)

736055.063 A

736055.521 B

736055.896 C

736056.063 A

736056.521 B

736056.896 C

736057.063 A

736057.521 B

736057.896 C

edit: example of desired, full array was incorrect, now fixed!

Answer 1

[KALYAN ACHARJYA]

You canot combine numeric and strings together in an Array, You may do the same using cell array. Another way using table

A=[736055.063,736056.063,736057.063];
B=[736055.521,736056.521,736057.521];
C=[736055.896,736056.896,736057.896];
data=[A',B',C'];
dat=data(:);
cate=['A','B','C']';
r=length(dat)/length(cate);
col2=repmat(cate,[r,1]);
t=table(dat,col2)

Result:

t =
  9×2 table
       dat        col2
    __________    ____
    736055.063     A  
    736056.063     B  
    736057.063     C  
    736055.521     A  
    736056.521     B  
    736057.521     C  
    736055.896     A  
    736056.896     B  
    736057.896     C  

[KALYAN ACHARJYA]

Here:

A=[736055.063,736056.063,736057.063];
B=[736055.521,736056.521,736057.521];
C=[736055.896,736056.896,736057.896];
data=reshape([A;B;C],size(A,1),[]); 
dat=data(:);
cate=['A','B','C']';
r=length(dat)/length(cate);
col2=repmat(cate,[r,1]);
t=table(dat,col2)

Result:

t =
  9×2 table
       dat        col2
    __________    ____
    736055.063     A  
    736055.521     B  
    736055.896     C  
    736056.063     A  
    736056.521     B  
    736056.896     C  
    736057.063     A  
    736057.521     B  
    736057.896     C  

[Claire]

Thank you this works perfect!