# Linear programming code not showing the solution

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Hmm! on 27 Feb 2021
Commented: Hmm! on 28 Feb 2021
I extracted the following code from an online pdf that solves basic feasible solution of linear programming problems.
function vert = feassol(A, b)
% Basic feasible solutions vert to the system of constraints
% Ax = b, x >= 0.
% They are stored in columns of the matrix vert.
[m, n] = size(A);
warning off
b = b(:);
vert = [];
if (n >= m)
t = nchoosek(1:n,m);
nv = nchoosek(n,m);
for i = 1:nv
y = zeros(n,1);
x = A(:,t(i,:))\b;
if all(x >= 0 & (x ~= inf & x ~= -inf))
y(t (i, :)) = x;
end
end
else
error('Nuber of equations is greater than th neumber of variables.')
end
if ~isempty(vert)
vert = delcols(vert);
else
vert = [];
end
end
To test the code, the author used the system
A = [1 1 1 0; 0 1 0 1];
b = [6; 3];
and obtain the results
vert = feassol(A, b)
vert =
0 0 3 6
0 3 3 0
6 3 0 0
3 0 0 3
But whenever I run the code, I get
>> vert = feassol(A,b)
vert =
[]
What am I not doing right with the code? Any help will be much appreciated. Thanks in advance!

Walter Roberson on 27 Feb 2021
Where do you assign something nonempty to vert?
Why do you calculate y since you never use it?
Hmm! on 28 Feb 2021
Sorry. It is another written function that I had to called. I have just figure it out.

Matt J on 27 Feb 2021
Edited: Matt J on 27 Feb 2021
As long as your feasible set is bounded, you can use this FEX submission instead,
A = [1 1 1 0; 0 1 0 1];
b = [6; 3];
vert=lcon2vert(args{:}).'
for which I get the result,
vert =
6.0000 3.0000 -0.0000 -0.0000
0.0000 3.0000 3.0000 -0.0000
-0.0000 0 3.0000 6.0000
3.0000 0 0 3.0000