Find row number of elements

Hi, I have a list of branches, BL, and a list of nodes, nodeList.

BL has two columns, containing to-from nodes for each branch. All elements in nodeList are included at least once in BL.

I want to create a list of branches that are connected to one or more nodes in nodeList.

What I want to achieve:

BL =

     1     2
     1     3
     2     4
     3     4
     4     5
     5     6

nodeList =

     1
     3

tempBranch =
     1
     2
     4

The way I'm doing it now (below) is very ineffective, so I'm hoping someone knows a better way to do this.

Can I do this without loops?

for j = 1:rows      %%rows in BL
    if BL(j,1) == nodeList(i) || BL(j,2) == nodeList(i) 
      tempBranch(k) = j; 
      k = k + 1; 
    end 
end

Thanks!

Answer 1

[Azzi Abdelmalek]

tempBranch =find(any(ismember(BL,nodeList),2))

[John Doe]

Perfect =) Thanks!