Help with resolving out of memory

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I have a function generatin a value (Vehicle) and ID numbers (VID) for vehicles.
function[Vehicle,VID]=race(ID, HHPerson,nBEV,BEV,x,i2)
for j = 1:nBEV
if HHPerson(i2)>=x
for k=1:nBEV
%There is only one car if
if k==j
Vehicle{j,k}=BEV(:, j);
VID{j,k}=ID(j);
else
Vehicle{j,k}=BEV(:, j)+BEV(:, k);
VID{j,k}=[ID(j) ID(k)];
end
end
end
if HHPerson(i2)<x
for k22=1:nBEV
%There is only one car if
Vehicle{j, k22} = BEV(:,k22);
VID{j, k22}= ID(k22);
end
end
end
end
The size of the cells are 108x108, In Vehicle, every cell contains a 525600x1 double and in VID, every cell contains one ore two numbers.
This is the error message:
Out of memory. Type HELP MEMORY for your options.
Error in race (line 11)
Vehicle{j,k}=BEV(:, j)+BEV(:, k);
Error in H2 (line 25)
[Vehicle1, VID1]=race(ID,HHPerson,nBEV,BEV,x,C);
Error in A1337 (line 212)
[GUD,GUDID]=H2(ID2,HHPerson,nBEV,BEV,x,Hcombos,Household,sample,A);
The initial size of the cells was 429x429, so I've already tried reducing the nr of vehicles included. Is there any way to circumvent the memory limit? The size of the cells is already preallocated as well and my memory is 64 GB

Accepted Answer

Walter Roberson
Walter Roberson on 19 Apr 2021
You should be preallocating the cell array Vehicle and VID as cell(nBEV,nBev}
The size of the cells are 108x108, In Vehicle, every cell contains a 525600x1 double
bytes_needed = 108 * 108 * 525600 * 8
bytes_needed = 4.9045e+10
gigabytes_needed = bytes_needed / 2^30
gigabytes_needed = 45.6765
You have problems unless you have more than 46 gigabytes.
  3 Comments
Walter Roberson
Walter Roberson on 19 Apr 2021
Probably yes, 91+ gigabytes for two such arrays.

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