how to create an array(1 by 5000) having random values in the range(9-11).

i have to put the array value as input for sine function, but i guess there are certain limitations for that. it would be great if you could help P.S: new to matlab excuse my immaturity.

Answer 1

[Image Analyst]

Did you look in the help? It's example 1:

Example 1
Generate values from the uniform distribution on the interval [a, b]:
 r = a + (b-a).*rand(100,1);

just change 100,1 to 1,5000, and change a to 9 and b to 11, like this:

r = 9 + 2 .* rand(1,5000);

By the way, what does "in sine" mean?

[sanky kumar]

i have to put the array value as input for sine function, but i guess there are certain limitations for that. it would be great if you could help P.S: new to matlab excuse my immaturity.

[Image Analyst]

I don't know if you mean that you want the random values to be the angle input to the sine,

out = sin(r);

or if you want to add those values to the sine wave:

x = linspace(0, 4*pi, length(r));  % Define angles.
noisy_y = amplitude * sin(x) + r;

Answer 2

[Azzi Abdelmalek]

9+rand(1,5000)*2

[sanky kumar]

thank you