How does code working in matlab ?

inverse_binary=not(handles.bw);
[handles.Lhandles.Num_object]=bwlabel(inverse_binary);
set(handles.text2,'string',10-handles.Num_object);

6 Comments

Can you clarify, what does set and bwlable do ?
L = bwlabel(BW) returns the label matrix L that contains labels for the 8-connected objects found in BW.
set() changes the properties of an object. In particular, the property named string of the object designated by handles.text2 will be changed to reflect the value 10-handles.Num_object
How does code working in matlab?
inverse_binary=not(handles.bw)
How can i explain if anyone asking me how does code working in matlab? I used that code for getting ouput for Available slots in Image processing method , I mentioned below that code which are i used for my project.
handles.output=hObject;
inverse_binary=not(handles.bw);
[handles.Lhandles.Num_object]=bwlabel(inverse_binary);
set(handles.text2,'string',10-handles.Num_object);
imshow(handles.L, 'parent',handles.axes2);
guidata(hObject,handles);
We assume that handles.bw has been assigned the result of thresholding the image into black and white, 0 and 1. The "not" operator takes logical negation, replacing false (0) with true (1) and true (1) with false (0). The result effectively reverses black and white -- reverses foreground and background.
For example if you were looking black text on white background then the text would be 0, but (by convention) the processing routines such as labelling work mostly on 1s, so you want to change the black-on-white to white-on-black
Imagine a case where the parking lot pavement is pretty much black, and the cars are distinguishablely something brighter. Then you threshold the image. The black parking lot would be 0 and the cars would be 1. Now take the logical negation so that the 0 (pavement) becomes 1 and the 1 (cars) becomes 0. Now you can label the result, and each blob of 1s will correspond to a section of adjacent available parking spaces.
Questions for you to think about:
  • how can you distinguish between adjacent available spaces? Are the edges of the spaces marked?
  • how can you deal with black cars, since those are dark too?

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 Accepted Answer

inverse_binary=not(handles.bw);
[handles.L, handles.Num_object]=bwlabel(inverse_binary);
set(handles.text2,'string',10-handles.Num_object);
You were missing a comma.

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