Need help finding the right PDE coefficients of this equation
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Hi everybody,
I can't figure out what are the coefficients of this equation in comparison with PDE toolbox parabolic equation format, any suggestion is really appreciated:

or its tensor equivalent:

Theta is a scalar and the domain is in x-z plane.
thanks,
Mohammad,
6 Comments
Bill Greene
on 24 Oct 2013
I might be able to suggest something but I don't understand either version of your equation.
In the first equation, what is del(z)? Is that the vector (0,0,1)? Isn't div(del(z)) equal zero?
In the second version, what is h? What are the ranges for i and j for the 2D PDE Toolbox case? 1->2 or 1->3?
Beyond those questions, could you be more specific about where you are stuck?
Bill
Mohammad Monfared
on 24 Oct 2013
Edited: Mohammad Monfared
on 24 Oct 2013
Bill Greene
on 25 Oct 2013
OK. I believe there must be a problem with the equation. Obviously, d(theta)/dt is a scalar. So the terms on the RHS must be scalars too. The term div(-K)*del(z) just doesn't fit with the rest of the equation.
Bill
Bill Greene
on 25 Oct 2013
Sorry, I forgot to mention that the term we are talking about is the "f" coefficient-- not the "a" coefficient in PDE Toolbox terminology. "a" is zero in your case because you don't have a term multiplying theta. Like "a", "f" also must be a scalar. But if the purpose of del(z) is simply to extract a scalar term from K, just set "f" to that scalar and you should be all set.
Bill
Mohammad Monfared
on 25 Oct 2013
Mohammad Monfared
on 27 Oct 2013
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