Problem 1730. GJam: 2013 Rd1a Bullseye Painting

Created by Richard Zapor

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<a href = "http://code.google.com/codejam/contests.html">Google Code Jam</a> 2013 Round 1a Bullseye challenge is to determine how many full rings can be painted given an initial radius and an amount of paint.Given a radius r, central white zone, create black rings of width 1 cm separated by 1 cm given P ml of paint that covers pi sq-cm per ml of paint provided.<img src = "http://code.google.com/codejam/contest/images/?image=bullseye.png&p=2464487&c=2418487">Input: [r, p] Integer values, 1&lt;=r,P&lt;=1000. Always enough P for one ringOutput: RingsExamples:<pre class="language-matlab">[1 9] 1;
[1 10] 2;
[3 40] 3;
</pre><pre class="language-matlab">[1 1000000000000000000] 707106780 for Bullseye Large Number Challenge
</pre>Google Code Jam:The next competition starts in April 2014. See details from above link.This contest does not discriminate by age or against the superiority of Matlab, unlike ACM. Forty-seven Matlab contestants in GJam 2013 out of 21,273.Solutions to the various past Challenges in Matlab can be found via <a href = "http://www.go-hero.net/jam/13/solutions">GJam Solutions</a>.The Challenges have subsets with Large Number aspects which appear to favor C and Java. Binbin Qi is our last hope with his expertise in Matlab/Java BigInteger.Related Challenges:<pre class="language-matlab">1) Reading 64 bit input file
2) Bullseye Large Numbers r&lt;1E18, P&lt;2E18
</pre>Usage of regexp is verboten

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Problem 1730. GJam: 2013 Rd1a Bullseye Painting

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