Another trick: if the last 4 digits of the number are divisible by 16, the full number is divisible by 16. So far as I know, if the last X digits of a number are divisible by 2^X, the entire number is divisible by 2^X.
@James: nice trick! (and I guess the proof arises from 10^x being always exactly divisible by 2^x, so "iff" also applies?)
perhaps less interesting but I guess you could do the same with powers of 5, iff the last X digits of a number are divisible by 5^x, then the entire number is divisible by 5^x...
Factorize THIS, buddy
Duplicate each element of a vector.
Sum of series V
I Plead the Fifth
Lights Out 10 - 5x5, with wrapping, 6 moves
Radiation Heat Transfer — View Factors (2)
Divisible by n, prime vs. composite divisors
Scrabble Scores - 9
Combined Ages 3 - Non-symmetric, n ≥ 3
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