This problem is yummy! :-)
Simple & interesting.
The same as the surface area of a cylinder but without calculating the area of the bottom surface (circle) of the cylinder:
Having finished all 15 problem just to see what is the leading solution looks like. Then I realize smaller size doesn't mean the solution is better, often it is at the price of understand-ability.
Remember, in most cases, you write program for humans not for machines.
SA = ((2*pi*r*h)+(2*pi*(r^2)))-(pi*(r^2));
calculating surface area except the base area
I do not think this exercise is correct. As one should not put frosting below the cake, the area of the cake to put frost on is the area of the circle on top of it plus the area of the "bent" rectangle on its sides. Thus:
function SA = func_frosting2(r,h)
ARectangle = pi*r*h;
ACircle = pi*r^2;
SA = ARectangle + ACircle;
I think the current solution is misleading
simple and fun.
just tricky one.
Implement a ROT13 cipher
Remove the small words from a list of words.
Roll the Dice!
Largest Twin Primes
Calculate Inner Product
Plot Damped Sinusoid
Find the Oldest Person in a Room
Calculate a Damped Sinusoid
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