Consider the integer number sequence N (1 to infinity).
After each iteration, take out the (k+1)th elements; where k is the number of iteration.
you've to find the nth number in the remaining sequence after k-th iteration.
- N= 1 2 3 4 5 6 7 8 9 10 11 12 ...
- for k=1, N becomes --- 1, 3, 5, 7, 9, 11, 13, 15, 17, …
- for k=2, N becomes --- 1, 3, 7, 9, 13, 15, 19, 21, 25, …
- so for [k=2,n=8], output should be 21.
Solution Stats
Problem Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers14
Suggested Problems
-
Back to basics 18 - justification
209 Solvers
-
Magic is simple (for beginners)
11397 Solvers
-
193 Solvers
-
18374 Solvers
-
Let's get back to school, and create multiplication tables
241 Solvers
More from this Author174
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
