No unique solution. For me it is the last solution of the permutation matrix.
For which test statement is there not a unique solution? We need to fix the test suite if there are two answers of same score.
Sorry, it was a mistake.
The statement of the problem is incorrect: "the sum of the absolute values of the differences is zero." You want the smallest sum, but it isn't necessarily zero.
Is there any size constraint on this problem ? My solution is not getting accepted ...
Best solution without lookup table
Never thought for-loop can be used for a matrix.
Aww.. ran out of memory.
%the part of the code i cut out, should work in theory ..
fliplist = fliplr(list);
idx = triu(ones(length(list)),0);
for j = 1:length(idx)
idx2 = unique(perms(idx(j,:)),'rows');
[a b] = size(idx2);
for i = 1 : a
idxi = boolean(idx2(i,:)');
list2 = list;
list2(idxi,:) = fliplist(idxi,:);
list2 = list2';
list2 = list2(:);
dlist = abs(diff(list2));
val2 = sum(dlist(2:2:end));
if val2 < val
val = val2;
orientation = idxi';
if val == 0
Times 2 - START HERE
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