Classify numbers as abundant, deficient, or perfect - MATLAB Cody - MATLAB Central

Problem 60346. Classify numbers as abundant, deficient, or perfect

Difficulty:Rate
A number is perfect if the sum of its proper divisors (i.e., divisors excluding the number itself) is equal to itself. For example, 28 is perfect because 1+2+4+7+14 = 28. Cody Problems 1012, 2544, and 47458 deal with the perfect numbers.
If the sum of proper divisors is less than the number, it is called deficient, and if it is greater than the number, it is abundant. For example, 21 is deficient (1+3+7 = 11 < 21) and 24 is abundant (1+2+3+4+6+8+12 = 36).
Write a function to classify numbers as abundant, deficient, or perfect.

Solution Stats

66.67% Correct | 33.33% Incorrect
Last Solution submitted on Aug 18, 2024

Solution Comments

Show comments
Primes and Rough Numbers, Basic ideas
What is a rough number? What can they be used...
3
5

Problem Recent Solvers6

Suggested Problems

More from this Author291

Problem Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!
Go to top of page