Create n x 2n "mirror" matrix of this type:
For n = 2
m = [ 1 2 2 1
1 2 2 1 ]
For n = 3
m = [ 1 2 3 3 2 1
1 2 3 3 2 1
1 2 3 3 2 1 ]
This problem was fun. I was able to find a better way to solve beat my own solution. Not the best way though. But lot better.
Matrix indexing with two vectors of indices
How long is the longest prime diagonal?
Given a 4x4 matrix, swap the two middle columns
convert matrix to single column
length of a vector
Sum of series I
Sum of series VI
Sum of series VII
Sum of series III
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