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Image Analyst
Image Analyst
Last activity on 16 Oct 2023

The MATLABIST

(From "The Exorcist" movie poster)
Image Analyst
Image Analyst
Last activity on 16 Oct 2023

Albert Einstein uses MATLAB

Albert Einstein uses MATLAB
Image Analyst
Image Analyst
Last activity on 24 Oct 2023

Dynamic Field Name shaming

Dynamic Field Name shaming
Image Analyst
Image Analyst
Last activity on 16 Oct 2023

Dog shaming

We told you "NO!!!"
Image Analyst
Image Analyst
Last activity on 16 Oct 2023

I climbed the L-Shaped Peak

I climbed the L-Shaped Peak
Image Analyst
Image Analyst
Last activity on 16 Oct 2023

Choose your weapon

Choose your weapon
Image Analyst
Image Analyst
Last activity on 16 Oct 2023

Caution. This is MATLAB.

Caution. This is MATLAB.
MATLAB is the best programming language
Image Analyst
Image Analyst
Last activity on 16 Oct 2023

MATLABlypse Now

I love the smell of debugged MATLAB code in the morning. Smells like...Victory!
Shore
Shore
Last activity on 16 Oct 2023

Halloween Analysis using Thingspeak

Halloween Analysis of Many Aspects of Halloween Headquarters and Effects on USA
(Note to Chistopher: I used a simple ESP8266 generating random numbers for fields 1 thru 7, (0 to 100, 4000, 127, 30, 45, 200,000, 50,000) and 0 to 1 for field 8. And a couple of real sensor inputs.
https://thingspeak.com/channels/2278931
Halloween Analysis
In the past year, we've witnessed an exponential growth of ChatGPT and other Generative AI tools. AI has quickly become a transformative force across industries, from tech giants to small startups, and even community sites like ours. For instance, Stack Overflow announced its plan to leverage AI tools to draft a question or tag content; Quora built a ChatGPT bot to answer questions; and GitHub is piloting the AI tool for personalized content.
This trend in the community landscape makes me wonder what MATLAB Central community, especially in MATLAB Answers, can do to integrate AI and enhance the community.
Share with us your ideas in the comment session. Ideally one comment per idea, so that others can vote on a secific idea or have deeper discussions about it.
We launched the Discussions area with 6 channels, based on the existing types of content we see today in the MATLAB Central community.
I'm curious which channels you are most interested in participating, or which channels are missing.
Tell us your thoughts here!
Chen Lin
Chen Lin
Last activity on 16 Oct 2023

The Community Snacks!

I'm in a community conference in Boston today and see what snacks we get! The organizer said it's a coincidence, but it's definitly a good idea to have them in our MathWorks community meetings.
Image Analyst
Image Analyst
Last activity on 3 Oct 2023

The new release is here!

(Sorry - it should be 2023b by now.)
Mike Croucher
Mike Croucher
Last activity on 10 May 2024

spy easter egg

spy
Rena Berman
Rena Berman
Last activity on 11 Oct 2023

PUZZLE: MATLAB-related word scramble

To solve the puzzle, first unscramble each of the words on the left. Then rearrange the letters in the yellow shaded boxes to complete the sentence on the right.
If you enjoyed this puzzle let me know with a like or in the comments below and I'll post more of them. Please don't post your answer, or any hints, and spoil it for those who come across this puzzle after you!! If you want to check your answer, you can messge me your guess through the link on my profile card (click on my name, Rena Berman, above and then on the envelope icon in the top right corner of the profile card that appears).
Thats the task:
Given a square cell array:
x = {'01', '56'; '234', '789'};
return a single character array:
y = '0123456789'
I wrote a code that passes Test 1 and 2 and one that passes Test 3 but I'm searching a condition so that the code for Test 3 runs when the cell array only contains letters and the one for Test 1 and 2 in every other case. Can somebody help me?
This is my code:
y = []
[a,b]=size(x)
%%TEST 3
delimiter=zeros(1,a)
delimiter(end)=1
delimiter=repmat(delimiter,1,b)
delimiter(end)=''
delimiter=string(delimiter)
y=[]
for i=1:a*b
y = string([y x(i)])
end
y=join(y,delimiter)
y=erase(y,'0')
y=regexprep(y,'1',' ')
%%TEST 1+2
for i=1:a*b
y = string([y x(i)])
y=join(y)
end
y=erase(y,' ' )